By L.F. McAuley

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Tan20 - 2V3 tan 0 1 = O. 1) sin 0 V2 = sin2 0 - 2(V2 V2) cos 0 V2 cos 2 0 - (2 47. V3(tan 48. 49. 60. 61. 4 3 3 4 2 + cos2 0 - Ans. 300. Ans. 300, 600. Ans. 300. + 2(1 63. 3 tan2 0 - 4V3 + + + V3) cos tan 0 +4 + + 0 + V3 = O. Ans. 300. = O. O. Ans. 300, 450. Ans. 00, 450. = O. Ans. 300, 600. 64. 2 cos 0 - cot 0 = O. 66. 4 sin 2 0 - 5 sin 0 1 = O. 66. tan 0 (sec0 - V2) = V3 (see0 - V2). + + 67. 4 sin2 0 - 3V6 sin 0 3 = O. 68. 7 cos2 0 - 29 cos 0 + 4 = O. 69. 2 cos2 0 - sin 20 = O. 60. tan 0 see 0).

Sin (-450). 32. sin 145°. 37. sin 700°. 42. cos (-325). What is the value of each of the following: 43. 3 sin (90° + e) + 4 cos (180° - e). 44. 3 sin (360° - e) - 3 cos (270° + e). FUNCTIONS 70 OF LARGE ANGLES 71 PLANE AND SPHERICAL TRIGONOMETRY 46. 2 tan (180° - (J) - 2 cot (90° + (J). 46. 5 sin (270° + (J) - 3 sin (270° - (J). 47. 4 cos (180° - (J) + 5 sin (270° + 82. If tan 200° = c, find 0). Show that the following are true equalities: 48. tan (225° 49. sin (135° - 0) + 0) = tan (45° = cos (45° - + 0).

Thus, in (3) if a and A are given, c = . sm A i if c and A are given, a = c sin A i and if a and c are given, A. = J:5in-1~. C . -Solve each of the above formulas for each letter in terms of the others. SOLUTION OF RIGHT TRIANGLE BY NATURAL FlTNCTIONS 41. -In solving a triangle, it is of the greatest importance to follow some regular order. The following is suggested: (1) Construct the triangle carefully to scale, using compasses, protractor, and ruler. The required parts can then be measured and a check obtained on the computed values.

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